Binomial Distribution Part II
Example
Aa x aa, family size = 8
P (7 Aa and 1 aa) progeny
There are eight different orders that include seven
Aa and one aa progeny in a family of eight progeny.
The probability of each of these orders is (1/2)8=
1/256.
P (Aa Aa Aa Aa Aa Aa Aa aa) = 1/256
P (Aa Aa Aa Aa Aa Aa aa Aa) = 1/256
P (Aa Aa Aa Aa Aa aa Aa Aa) = 1/256
P (Aa Aa Aa Aa aa Aa Aa Aa) = 1/256
P (Aa Aa Aa aa Aa Aa Aa Aa) = 1/256
P (Aa Aa aa Aa Aa Aa Aa Aa) = 1/256
P (Aa aa Aa Aa Aa Aa Aa Aa) = 1/256
P (aa Aa Aa Aa Aa Aa Aa Aa) = 1/256
P (seven Aa, one aa) = 8/256
The coefficient of 8 is provided by the following formula:
Where n = total number in sample; r = number of 'successes';
n-r = number of 'failures'.
n=r+(n-r)
