Two Segregation Ratios Possible

Chi Squared Short Formula

Hypothesis

Example

Another Example

F2 Data in Coupling Phase Linkage

F2 Data in Repulsion Phase Linkage

  Click here for a
printer-friendly version

Hypothesis

9:7 hypothesis 3:1 hypothesis
class dominant recessive Total domiant recessive
obs. 63 32 95 63 32
exp 53.44 41.56 95 71.25 23.75
X2=(63-53.44)2+(32-42.56)2
        53.44           41.56
X2(63-71.25)2+(32-23.75)2
        71.25         23.75
= 1.710 + 2.199
= 3.91
reject 9:7
= 0.955 + 2.866
= 3.82
accept 3:1

Even with the worst case scenario of the observed numbers having the ambiguous ratio, we can still distinguish between the two hypothesis when n=95.

If we use n=95 and calculate the expected number of recessives for each of the two hypothesized ratios, we get:

Ho:3:1 1/4(95) = 23.75~24
Ho:9:7 7/16(95) = 41.6~42

The mean is (42+24)/2 = 32. Therefore when n =95 and we have more than 32 recessives we would accept the 9:7 ratio. If we have fewer than 32 recessives we would accept the 3:1 hypothesized ratio.

Copyright 2000©, Ted Helms

Back | Home | Top | Next
Home Forward Back