Conditional Probability

Mean Value of Each Marker Class

QTL Mapping and Marker Mean: F2 Population

Marker Assisted Selection (MAS)

Conclusions about QTL Mapping

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QTL Mapping and Marker Mean:
F2 Population

Example:

Say u1=2, u2=1, u3=0. The marker and QTL are in coupling phase linkage for an F2 population and r = 0.2. Find the mean for each marker genotype and the overall mean.

uAA = (1-r)2u1 +2r(1-r)u2 + r2u3
      = (0.8)2(2) + 2(0.2)(0.8)(1) + (0.2)2(0)
      = 1.28 + 0.32 + 0
      = 1.6

uAa = r(1-r)u1 + [(1-r)2 + r2]u2 + r(1-r)u3
      = 0.2(0.8)(2) + [(0.8)2 + (0.2)2](1) + (0.2)(0.8)(0)
      = 0.32 + 0.68 + 0
      = 1

uaa = r2u1 + 2r(1-r)u2 + (1-r)2u3
      = (0.2)2(2) + 2(0.2)(0.8)(1) + (0.8)2(0)
      = 0.08 + 0.32
      = 0.40

u = 1/4uAA + 1/2uAa + 1/4uaa
   = 1/4(1.6) + 1/2(1) + 1/4(0.4)
   = 0.4 + 0.5 + 0.1
   = 1

Now let's say that r=0.4, u1=4, u2=1, u3=-2. Find the uAA, uAa, uaa and the overall mean(u).

uAA = (1-r)2u1 + 2r(2-r)u2 + r2u3
      = (0.6)2(4) + 2(0.4)(0.6)(1) + (0.4)2(-2)
      = 0.36(4) + 0.48(1) + 0.16(-2)
      = 1.44 + 0.48 - 0.32
      = 1.6

uAa = r(1-r)u1 + [(1-r)2 + r2]u2 + r(1-r)u3
      = 0.4(0.6)(4) + [(0.6)2 + (0.4)2](1) + 0.4(0.6)(-2)
      = 0.96 + 0.52 - 0.48
      = 1


uaa = r2u1 + 2r(1-r)u2 + (1-r)2u3
      = (0.4)2(4) + 2(0.4)(0.6)(1) + (0.6)2(-2)
      = 0.64 + 0.48 - 0.72
      = 0.4

u = 1/4uAA + 1/2uAa + 1/4uaa
u = 1/4(1.6) + 1/2(1) + 1/4(0.4)
u = 1

The results show that when r=0.2 and u1=2, u2=1, u3=0 the means of each marker class are uAA=1.6, uAa=1, uaa=0.4. The results also show that when r=0.4 and u1=4, u2=1, u3= -2 the means of each marker class are uAA=1.6, uAa=1, uaa=0.4.

The marker class means did not change as r was varied, but the means of each QTL genotype did change.

r = 0.2 r = 0.4
Marker
Genotype
Marker
Mean
QTL
Value
Marker
mean
QTL
value
Aa uaa = 1.6 u1 = 2 uAA =1.6 u1 = 4
Aa uAa = 1.0 u2 = 1 uAa = 1.0 u2 = 1
aa uaa = 0.4 u3 = 0 uaa = 0.4 u3 = -2
overall u = 1   u = 1  

Conclusion:

For the case of a single marker, linkage values between the marker (only true for the case of single marker) and QTL are confounded with QTL value. The only information we have is the mean of each marker class. In out example we know that the means of the AA, Aa, and aa marker classes are 1.6, 1.0, and 0.4, respectively. If r = 0.2 then the associated effects of the QQ, Qq, and qq QTL genotypes are 2, 0, and 1, respectively. If r = 0.4, then the marker class means are the same, but the effects of the QQ, Qq, and qq QTL genotypes are 4, 1, and -2, respectively.

Copyright 2000©, Ted Helms

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