Percent Recombinant Genotypes versus Map Distance

Haldane's Mapping Function

Gametic Probabilities for Three Linked Loci

Expected Frequency Example I

Expected Frequency Example II

Poisson Distribution

An Example

Kosambi's Map Function

Summary Of Map Distance Versus Observed Recombination Fraction

Homework Assignment #8 Questions

 

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An Example

r estimated from observed recombination = 0.30.

r = 1/2(1 - e-2d) = 0.30
1 - e-2d = 0.60
0.4 = e-2d
ln(0.4) =-2d
-ln(0.4) = 2d
-(-0.916) = 2d
d = 0.458

l is the mean number of crossover events. Each crossover results in 50% recombination. Then l/2 = m.
m = recombination fraction

** The observed recombination percent was 0.3, the actual relative frequency of recombinant types is 0.458. The adjusted recombination percent is multiplied by two to equal the crossover percent. This is because each crossover event results in 50% non-parental gametes. The map is 45.8cM.

Haldane's mapping function converts the relationship of the sum of two intervals to the sum of the total interval into a linear relationship.

rAC does not equal rAB + rBC

dAC = dAB + dBC

pg 20. Liu, B.H. Statistical Genomics.

Copyright 2000©, Ted Helms

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