Use to Detect Linkage in Testcross

Example 1

Example 2

Orthogonality

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Example 2

Strickberger. pg 317

Cross AaBb x AaBb and expect F2 ratio of 9:3:3:1 with complete dominance gene action at each locus and no linkage.

  A_B_ A_bb aaB_ aabb Total
observed 180 30 60 10 280
expected 157.5 52.5 52.5 17.5 280

X2 = (180-157.5)2 = (30-52.5)2 + (60-52.5)2 + (10-17.5)2
157.5 52.5 52.5 17.5

= 17.14 w/3df which is significant

There are three possible explanations from the significant deviation from the expected 9:3:3:1 ratio. Explanations include: Deviation from 3:1 ratio at 'A' locus; deviation from 3:1 ratio at 'B' locus; lack of independent assortment between the two genes due to linkage.

A Locus

  A_ aa Total
observed 180+30=210 60+10=70 280
expected 210 70 280

X2 = 0  w/1df, not significant accept Ho:3A_:1aa.

B Locus

  B_ bb Total
observed 180+60=240 30+10=40 280
expected 210 70 280

X2 = 17.14  w/1df, significant so reject Ho:3B_:1bb

Linkage

Contingency X2 test w/1df

  B_ bb  
A_ 180 30 210
aa 60 10 70
  240 40 280

X2 = [|(180)(10)-(30)(60)| - ½(280)]2  x 280    
(240)(40)(210)(70)    

= [|0 - ½(280)|]2 x 280 = 0        
(240)(40)(210)(70)        

So fail to reject Ho: independence between A and B

Conclusion

There is no distortion in the segregation ratio for the 'A' locus. There is a distorted segregation ratio for the 'B' locus. There is no indication that the two loci are not segregating independently.

** "Even distorted segregation ratios will not affect the test for linkage." This is because the three tests are orthogonal. We will show this.

Copyright 2000©, Ted Helms

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